50x^2-5x-3=(10x-3)

Solution for 50x^2-5x-3=(10x-3) equation:

50x^2-5x-3=(10x-3)

We move all terms to the left:

50x^2-5x-3-((10x-3))=0


We calculate terms in parentheses: -((10x-3)), so:

(10x-3)

We get rid of parentheses

10x-3

Back to the equation:

-(10x-3)


We get rid of parentheses

50x^2-5x-10x+3-3=0

We add all the numbers together, and all the variables

50x^2-15x=0

a = 50; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·50·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*50}=\frac{0}{100}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*50}=\frac{30}{100}
=3/10
$